Java project

Well, instead of using an integer use a double, that has a much higher number limit and saves every digit. If you find a way to max out a double, I will mail you my house.

this is the code i have though it can only hold 2147483647.. any number higher than that i get the error message stating "integer number too large" import java.math.BigDecimal; public class AddTwoBigNumbers{ public static void main() { BigDecimal num1, num2; num1 = new BigDecimal(2147483647); num2 = new BigDecimal(2147483647); Sum(num1, num2); } public static void Sum(BigDecimal val1, BigDecimal val2){ BigDecimal sum = val1.add(val2); System.out.println("Sum of two BigDecimal numbers: "+ sum); } }

this is the code i have though it can only hold 2147483647.. any number higher than that i get the error message stating "integer number too large" import java.math.BigDecimal; public class AddTwoBigNumbers{ public static void main() { BigDecimal num1, num2; num1 = new BigDecimal(2147483647); num2 = new BigDecimal(2147483647); Sum(num1, num2); } public static void Sum(BigDecimal val1, BigDecimal val2){ BigDecimal sum = val1.add(val2); System.out.println("Sum of two BigDecimal numbers: "+ sum); } }

Double does *not* save every digit, it has a precision of 64 bits only, and does not save any more digits that that. It does use a floating point notation which allows it to achieve the high values that it does. To answer 151mewtwo's question, there is a class called BigInteger, which can store integers as large as you want. I think this will solve your problem, just make sure your instructor doesn't actually want you to write your own class instead of implementing another.

Technically the precision is only 53 bits :) Only 52 bits of significand are actually stored because the first bit is always assumed to be 1 (except in the case of zero or "not-a-number" values); the rest of the 64 bits is comprised of 11 exponent bits and 1 sign bit. But that's getting off track... :) 151mewtwo, try: BigDecimal num1 = new BigDecimal("1000000000000000000000000000000000"); (for example). I'd also question whether it's BigDecimal or BigInteger that you should be using - if you don't need to support numbers with a decimal point, use BigInteger as it's slightly more efficient.

hey davmac, BigDecimal num1 = new BigDecimal("1000000000000000000000000000000000"); this code really worked... thanks.. and thanks also to all those who replied... appreciate it.. but i have one more thing, how to ask for user input for two numbers? and how to check if the user input is using decimals or just integers.. -thanks